Thursday, October 10, 2013

Classifying Chemical Reactions

Thursday, October 10th

Homework Review
We went over the two worksheets that were due today. (Classifying, Predicting, and Balancing, Oh My! and Types of Reactions). We had to solve this equation for homework as well copper (II) sulfate reacts with sodium phosphate to produce sodium sulfate and copper (II) phosphate.
      We also reviewed the types of reactions: combination reaction, decomposition reaction, combustion reaction, single replacement reaction, and double replacement reaction.
       If you were absent today the answer keys to the homework are in the Unit 3 Keys folder.

Notes
Today in class we did a lab. The lab was classifying chemical reactions
Here is the data:
Short video of reaction 1:


Homework
1) The key to the Classifying Reactions HW sheets is posted.  The "Predicting Products Practice" (Ws #1 and #2) that are part of these HW sheets are optional, but I highly recommend that you do them on your own and check your work against the key.  THERE IS A QUIZ TOMORROW and this will help you prepare!

2) Complete the Classifying Chemical Reactions Lab packet that goes with today's lab.  If you were absent, check the blog for lab data and use that to complete the packet.  Due tomorrow.


Next Blogger: Pamela H. 


Wednesday, October 9, 2013

Balancing More Equations and Types of Chemical Reactions

Wednesday, October 9th


Homework Review

We spent the first part of class today going over the two worksheets that were assigned for homework last night.  The key for these worksheets is posted here.  If you were absent on Tuesday, the blank copies are in the Unit 3 Handouts folder.  We were only supposed to do the odd number problems for the Balancing Chemical Equations worksheet, but the answers to the even problems are also posted if you want extra practice.

Number 9 on the Balancing Chemical Equations worksheet is a good problem to look at because it uses a decimal to balance the equation (which we learned how to do yesterday):

__ C8H18 + __ O2          >         __ CO2 + __ H2O

On the left side, we start off with 8 carbons, 18 hydrogens, and 2 oxygens.
On the right, we have 1 carbon, 2 hydrogens, and 3 oxygens.
First we balance the carbon atoms:

__ C8H18 + __ O2          >        8CO2 + __ H2O

This gives us 8 carbons, 18 hydrogens, and 2 oxygens on the left, and 8 carbons, 2 hydrogens, and 17 (8*2+1) oxygens on the right. To balance the hydrogen, you multiply the H2O by 9.

__ C8H18 + __ O2          >        8CO2 + 9H2O

We now have 8, 18, and 2 on the left, and 8 carbons, 18 hydrogens, and 25 (8*2+9) oxygens on the right. Now we can balance out the oxygens by multiplying the oxygen gas on the left side by the decimal 12.5.

__ C8H18 + 12.5O2          >        8CO2 + 9H2O

The equation is now balanced, but we have to multiply the whole thing by 2 to get all whole numbers, which gives you the answer

2C8H18 + 25O2          >        16CO2 + 18H2O

*tip: when given a reaction with carbon, hydrogen, and oxygen, balance them in the order CHO!

Pop Quiz

After we checked our homework, Mrs. Friedmann announced that we had a pop quiz, which caused anxiety attacks for many of us. However, it was only one problem for a single point and we were allowed to use our notes. The problem we had to answer read:

Aluminum nitrate reacts with magnesium oxide to make magnesium nitrate and aluminum oxide.

Put into equation form (don't forget to balance the charges!), this would look like:

__ Al(No3)3 + __ MgO          >         __ Mg(No3)2 + __ Al2O3

On the left, we have 1 aluminum atom, 3 nitrates (if you don't split it up), 1 oxygen and 1 magnesium. On the right, we have 2 aluminums, 2 nitrates, 3 oxygens, and 1 magnesium. First, I balanced the aluminum:

2Al(No3)3 + __ MgO          >         __ Mg(No3)2 + __ Al2O3

There are now 2 aluminums, 6 nitrates, 1 oxygen, 1 magnesium on the left, and 2 aluminums, 2 nitrates, 3 oxygens, and 1 magnesium on the right.  I now balanced the nitrates like so:

2Al(No3)3 + __ MgO          >         3Mg(No3)2 + __ Al2O3

You now have 2 aluminums, 6 nitrates, 1 oxygen, and 1 magnesium on the left, and 2 aluminums, 6 nitrates, 3 oxygens and 3 magnesiums on the right. What is now left to balance are the magnesium and oxygen atoms, which we can conveniently balance by multiplying MgO by 3.

2Al(No3)3 + 3MgO          >         3Mg(No3)2 + __ Al2O3

The equation is now balanced. The answer is:

2Al(No3)3 + 3MgO          >         3Mg(No3)2 + Al2O3


Notes

We spent the rest of class taking notes on the five common types of chemical reactions. Here is an overview.

1. "Put It Together" Combination Reaction

Two elements combine to make a compound. Opposite of a decomposition reaction.

A + B > AB

Ex: 2Mg + O2 > 2MgO


2. "Take It Apart" Decomposition Reaction

A more complex compound breaks up into simple elements. Opposite of a combination reaction.

AB > A + B

Ex: 2H2O2 > 2H2O + O2


3. "Trade One Place" Single Replacement Reaction

An element replaces one of the ions in an ionic compound ONLY if element is more active than the ion. We received an Activity Series Chart to use for this (posted on moodle) that shows which elements are more or less active than others. Elements cannot replace anything above them. If this happens, the reaction does not occur. For finding out which ions to switch with the element, think "like replaces like."

If the element is a metal it replaces the metal (positive) ion:

A(<metal) + B(<metal)C > B + AC (A replaces B)

If the element is a nonmetal it replaces the nonmetal (negative) ion:

A(<nonmetal) + BC(<nonmetal) > C + BA (A replaces C)

Metal Ex: 2Al + 3CuSO4 > 3Cu + Al2(SO4)
*notice how in the product, there are 2 atoms of Al and 3 of SO4, instead of just Al replacing Cu. Don't forget to balance out the charges!

Nonmetal Ex: F2 + 2NaCl > Cl2 + 2NaF


4. "Trade Two Places" Double Replacement Reaction

Two ionic compounds trade positive (front) ions. Remember "like replaces like." (You do not need to use the Activity Series Chart for these.)

AB + CD > CB + AD


5. "Burn!" Combustion Reaction (aka CHO Reaction)

A compound made of H and C (known as a hydrocarbon) reacts with O2 to make CO2 and H2O. You always get carbon dioxide and water with combustion reactions. Combustion reactions are the burning of anything organic.

CxHy + O2 > CO2 + H2O

Homework

We have two sheets due tomorrow. These can be found on moodle under the name Classifying Reactions HW Sheets in the Unit 3 Handouts.

Balancing Word Equations and More!

Tuesday October 8th, 2013


1. Review Worksheets that were for homework
If you missed yesterday, we went over the homework reviewing balancing equations that was assigned last friday, Here are the answers to each question, just giving the number that should be before the equations in order.
  1. 2,3,2,3
  2. 1,2,1,2
  3. 2,2,2,1
  4. 1,2,2,1
  5. 1,2,1,2
  6. 3,1,1,3
  7. 2,3,1,6
  8. 1,2,2,1,1
  9. 2,2,1
  10. 2,2,1
  11. 2,1,1
  12. Balanced
  13. 2,1,2
  14. 1,2,1,2,1
  15. Balanced
  16. 1,3,1
  17. 2,2,3
  18. 2,1,1,2
  19. 1,1,1,2,2
  20. 3,1,1,3
Mrs. Friendmann also explained to us that the equation AgCH3COO can be re-written as AgC2H3O2.
We also learned that when balancing equations you can use decimals, and then just multiply the answer by 2 as follows.

C(4)H(10) + O(2) -----> CO(2) + H(2)O

When you try to balance the equation, you'll find that its easiest to do it like this:

C(4)H(10) + 6.5 O(2) --------> 4 CO(2) + 5 H(2)O

Yet since we need whole numbers as our multipliers, we can just multiply the equation by 2 to get the answer we need. Here is the final equation:

2 C(4)H(10) + 13 O(2) ------> 8 CO(2) + 10 H(2)O

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2. Balancing word equations

Mrs, Friedmann next assigned us two worksheets to work on tonight, one of which is the normal balancing equations and the other is balancing word equations. Balancing word equations is just like balancing formula equations, except you have to add the extra step of finding the formulas for the names of the compounds. You also have to remember Prof. HONClBrIF in order to accurately get the formulas of all the diatomic elements. So if you see the name Chlorine Gas, its not Cl, its Cl(2) because it is diatomic. You can find examples of these on the moodle page, but if you don't feel like searching, I've done number 2 for you here.

Aluminum Bromide and Chlorine Gas react to form Aluminum Chloride and Bromine Gas

Formula:  AlBr(3) + Cl(2) ---------> AlCl(3) + Br(2)

Now that the equation is written in formula form, we can simply balance. Here is the final answer:

2 AlBr(3) + 3 Cl(2) ----------> 2 AlCl(3) + 3 Br(2)

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3. Tests!

For the last 30 minutes of class we went over the tests in small groups, working on fixing our errors on the word problems, hoping to understand what we did wrong. This lasted till the end of the period.

Next Blogger: Valerie Korol

Monday, October 7, 2013

Our First Chem Day

Don't worry if you weren't in class today because you didn't miss much. We went to the auditorium and watched an episode of the Discovery Channel show Mythbusters. The episode, from the fourth season of the show, was called "Crimes and Myth-demeanors". We filled out a worksheet for it, but I  imagine that it wouldn't hurt your grade if you weren't here.

While Mythbusters is a good show, we missed you Ms. Friemann!

If you didn't finish your homework this weekend, you do have utnil tomorrow to get it done.

Again, the next blogger is Daniel W.

Saturday, October 5, 2013

Balancing Equations in a Musical Fifth Period

Beginning of class

Mrs. Friedmann showed us a video of Mr. Lieberman singing “Friday” originally recorded by Rebecca Black as we walked into class, and comments about it lead to people talking about their favorite musicians. We went down the columns of desks for the first twenty minutes of class telling Ms. Friedmann (who took notes) about our favorite artists and songs.

If you weren't able to fully appreciate this wonderful rendition of the then thirteen year old one hit wonder's viral song, it can be enjoyed here: 



Law of Conservation of Mass

After that, we took notes on the law of conservation of mass. Ms. Freidmann’s notes can be found here: http://gbs-moodle.glenbrook225.org/moodle/file.php/12015/1314_Unit_3/Unit_3_Notes/10.4_Notes_on_Balancing.pdf
I originally planned to write my notes from class here, but since the ones on moodle are superior, I think it would be unnecessary and redundant. It’s important to remember that atoms in a chemical reaction are neither created nor destroyed, only rearranged (and therefor “conserved”). In other words, the atoms in the reactants must match those in the products.

End of Class

After practicing a few balancing problems from the homework, we watched a video on German and the music video for the Ylvis song “The Fox (What does the Fox say?”. If you’d like to see either one again, I’ve posted the links below.

German Language Compared to Other Languages: http://www.youtube.com/watch?v=ZlATOHGj9EY


Have a nice weekend and don’t forget to do the ChemThink and worksheets from class!

The next scribe is, as requested, Daniel W!

Wednesday, October 2, 2013

Partner Quiz and Applying Formulas

Partner Quiz and Applying Formulas


Colin S.
October 1st

Congratulations period 5, you failed!



     Mrs. Friedman gave back the partner quizzes we took yesterday to start the class. Everyone failed (no, this won't count toward your grade), but Mrs. Friedman explained to us the importance of failing. She talked to us about how important it was to fail, as we could learn from these experiences. This might be new to us because as Mrs. Friedman said up to this point we're all bad at failing. In order to be a scientist, failing is necessary.

    Mrs. Friedman also talked about how it is important to apply formulas, rather than just input numbers into them. The questions on the quiz were evidence of that. What you are given may not always be what you use to solve the problem.

   An important thing to note on the quiz is that when finding the number of H+ ions, for example, in H_2O, the ratio is 2 H+ ions: 1 molecule of H_2O.

    Also, there were some technical difficulties with video, but it is expected to be up by around 7.

The next blogger is:
Brandon M.

Tuesday, October 1, 2013

Percent Composition and the Formula of a Hydrate Lab

Percent Composition and the Formula of a Hydrate Lab

Hayden Northwick

September 27th and September 30th

September 27th:

The Percent Sugar in Gum Activity - An Introduction to "Percent Composition"

     At the beginning of class Mrs. Friedmann gave each of us a piece of gum to chew on.  We then weighed the gum before chewing it and after having chewed it for a while.  Then using that information, we were able to calculate the mass of the sugar in the gum, the percent sugar out of total mass of the gum, the moles of sugar and the moles of gum, and find the ratio of gum particles to sugar particles.  Then applying the information to real compositions, we were able to find out the percent mass of each element in lead(II) sulfate.  We could do this by first finding the mass of the entire compound, then finding the mass of the individual parts of the compound and dividing that by the total mass to come up with a percentage of each part.

September 30th:

The Hydrates Lab

     We did the Hydrates lab today.  Sample results are:

Mass of the test tube:  21.62g
Mass of the hydrate and the test tube: 23.79g
Mass of the hydrate and the test tube after heating both: 22.95g

Sorry for not posting this yesterday...

The next person to post on the blog is:
 Colin Samuels